-2[a – 2] = -3[b – 4]

Clear the bracket by multiplying LHS by -2 and RHS by -3:

-2a + 4 = -3b + 12

Collect like terms

-2a + 3b = 12 – 4

-2a + 3b = 8

-2[a – 2] = -3[b – 4]

-2a + 4 = -3b + 12

-2a + 3b = 12 – 4

-2a + 3b = 8…….(i) to prove that this is true

Let find the value of a and substitute in (i) above

-2a + 3b = 8

-2a = 8 – 3b

a = [8 – 3b] / -2

Substituting (a) in (i) we have

-2a + 3b = 8

-2[(8 – 3b)/ -2] + 3b = 8

8 – 3b + 3b = 8

8 = 8

Therefore, it is true that -2a + 3b = 8

-2(a-2)=-3(b-4)

Solution

-2(a-2)=-3(b-4)

-2a+4=-3b+12

Collect like terms

When minus(-) cross over it turns plus while when plus(+) crosses over it turns minus sign

-2a+3b=12-4

-2a+3b=8

Take note

+ × – = –

– × + = –

+ × + = +

– × – = +

So you use -2 to multiply your first bracket and use -3 bracket is multiplication because its in bracket cause you are using the number before the bracket to multiply all numbers in the bracket each like if you put the equation

-2×a-2=-3×b-4you get

-2a-2=-3b-4 because there is no bracket.

-2a+3b=8

-2xa – 2x-2= -3xb – 3x-4

-2a+4= -3b+12

Collect like term

-2a+3b=12-4

3b-2a=8

= 3b-2a=8

Nice and

a=8

correct