Please Simplify -2 [a – 2] = -3 [ b – 4 ]

-2a+3b=8

Thats -2a+3b=8

-2a + 3b - 8 = 0; Or -a2 + 3b = 8 That's the answer

3b-2a=8

-2a+3b=8

-2a+3b=8

-2a +3b =8

-2a+3b=8

-2[a - 2] = -3[b - 4] Clear the bracket by multiplying LHS by -2 and RHS by -3: -2a + 4 = -3b + 12 Collect like terms -2a + 3b = 12 - 4 -2a + 3b = 8  

-2[a - 2] = -3[b - 4] -2a + 4 = -3b + 12 -2a + 3b = 12 - 4 -2a + 3b = 8.......(i)  to prove that this is true Let find the value of a and substitute in (i) above -2a + 3b = 8 -2a = 8 - 3b a = [8 - 3b] / -2    Substituting (a) in (i) we have -2a + 3b = 8 -2[(8 - 3b)/ -2] + 3b = 8 8 - 3b + 3b = 8 8 = 8 Therefore, it is true that -2a + 3b = 8

= - 2a + 3b = 8

-2(a-2)=-3(b-4) =-2a+4=-3b+12 =-2a+3b=12-4 =-2a+3b=8  

-2a+3b=8

-2(a-2)=-3(b-4) Solution  -2(a-2)=-3(b-4) -2a+4=-3b+12 Collect like terms When minus(-) cross over it turns plus while when plus(+) crosses over it turns minus sign -2a+3b=12-4 -2a+3b=8 Take note + × - = - - × + = - + × + = + - × - = + So you use -2 to multiply your first bracket and use -3 bracket is multiplication because its in bracket cause you are using the number before the bracket to multiply all numbers in the bracket each like if you put the equation -2×a-2=-3×b-4you get -2a-2=-3b-4 because there is no bracket.   

3b-2a=8

-2a+3b=8